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  1. Wedge of Cheese

    I think I'm going to do some serious reworking to the underlying audio playback framework in my...

    I think I'm going to do some serious reworking to the underlying audio playback framework in my Java org player, which may take a few months, so don't upload it to the site yet. I'll let you know when it's ready.
  2. Wedge of Cheese

    Cave Story Remix Project 2

    Yeah, so I included both the really high notes and the not-so-high notes in the score. If you feel you can do the high notes well, then do them, otherwise don't.
  3. Wedge of Cheese

    Cave Story Remix Project 2

    http://www.mediafire.com/?lsone81c38xi4cj
  4. Wedge of Cheese

    <a href='http://www.mediafire.com/?s4596ixh8py621x' class='bbc_url' title='External link'...

    <a href='http://www.mediafire.com/?s4596ixh8py621x' class='bbc_url' title='External link' rel='nofollow external'>http://www.mediafire...s4596ixh8py621x</a> On my computer, it stutters at 40 kHz, does it do the same for you?
  5. Wedge of Cheese

    Cave Story Remix Project 2

    Cool beans. I'm going home the 1st weekend of February, so I'll be able to make an accomp-only recording then. I think I'll wait to add whatever bonus album art we have until you've done your recording, so I can re-upload all at once (there's the single ginormous file "Cave Story Remix Project...
  6. Wedge of Cheese

    I'm now going to do what I didn't do before and prove that these two filters are in fact...

    I'm now going to do what I didn't do before and prove that these two filters are in fact complimentary. However, in order for it to work right, I have to split the first line of the highpass into two lines: output+=input-prevInput; output-=2*Math.PI*cutoffFreq*output/samplingRate; At first...
  7. Wedge of Cheese

    Notice that, if K and w are equal, then the angular velocity response functions of the lowpass...

    Notice that, if K and w are equal, then the angular velocity response functions of the lowpass and highpass filters are equal. If K is greater, then that of the lowpass is greater, and if w is greater, then that of the highpass is greater. We're going to call the point at which they're equal...
  8. Wedge of Cheese

    We've already seen how to implement the lowpass filter in Java...

    We've already seen how to implement the lowpass filter in Java: output+=(signal-output)*controller; but let's make a couple small modifications. First, let's change the variable names: output+=(input-output)*k; Recall that K=k/delta_t, so k=K*delta_t. Furthermore, delta_t is just the...
  9. Wedge of Cheese

    tiem fur moar

    tiem fur moar
  10. Wedge of Cheese

    An Untitled Story

    AW YEAH finally beat this on difficult mode. And I've made it to the final boss on masterful (though I don't anticipate beating it any time soon... >_>)
  11. Wedge of Cheese

    Cave Story Remix Project 2

    IPBoard oddities aside, the new Lunar Eclipse is now on the site.
  12. Wedge of Cheese

    The differential equation which defines the high-pass filter is as follows: <span...

    The differential equation which defines the high-pass filter is as follows: <span rel='lightbox'><img src='http://latex.codecogs.com/gif.latex?\frac{d}{dt}HP(f)(t)=\frac{df}{dt}-K\cdot HP' alt='Posted Image' class='bbc_img' /></span> I'm not going to walk through proving that it satisfies the 2...
  13. Wedge of Cheese

    The other filter we're looking at is the "complimentary filter" to the low pass filter, and is...

    The other filter we're looking at is the "complimentary filter" to the low pass filter, and is called, logically, the high pass filter. Again, it's not the only high pass filter there is, just the only one we'll be looking at. It, too, has a K value as a parameter, and, as it turns out, if you...
  14. Wedge of Cheese

    Alright, since csrp2 with updated lunar eclipse is taking forever to upload, I might as well...

    Alright, since csrp2 with updated lunar eclipse is taking forever to upload, I might as well continue the postathon.
  15. Wedge of Cheese

    Cave Story Remix Project 2

    What the flying fuck? I swear I never even touched any formatting buttons :/
  16. Wedge of Cheese

    Cave Story Remix Project 2

    Glad you enjoyed it so much :D! The only thing I'm a bit confused about is why you'd want the "so calm.....so mellow...." Lunar Eclipse in sacred grounds, but whatever :p. And speaking of which, it seems I've forgotten to upload the new version of Lunar Eclipse. Will do this very soon. And...
  17. Wedge of Cheese

    I will conclude by explaining the significance of a transformation S with these two features...

    I will conclude by explaining the significance of a transformation S with these two features: 1) it's distributive over addition (S(f+g)=S(f)+S(g)) 2) the transformation of a sine wave is a sine wave with the same frequency (but not necessarily the same amplitude or phase) If we think of an...
  18. Wedge of Cheese

    Anyway, we'll assume that C is zero, since, as I pointed out before, we can start wherever we...

    Anyway, we'll assume that C is zero, since, as I pointed out before, we can start wherever we want. In practice, this isn't completely true, but even so, notice that as t gets larger, the C term approaches zero anyway (that was my main tipoff for the first one being wrong). The rest of the...
  19. Wedge of Cheese

    Actually, that's also incorrect, I typed a plus instead of a minus into wolfram. The correct...

    Actually, that's also incorrect, I typed a plus instead of a minus into wolfram. The correct answer is: <span rel='lightbox'><img src='http://latex.codecogs.com/gif.latex?S=C\cdot e^{-K\cdot t}+\frac{a\cdot K\cdot (K\cdot sin(\omega\cdot t+p)-\omega\cdot cos(\omega\cdot...
  20. Wedge of Cheese

    Actually scratch all that, I have solved that diffeq by hand before, but I can't remember how I...

    Actually scratch all that, I have solved that diffeq by hand before, but I can't remember how I did it. Wolfram says the solution is: <span rel='lightbox'><img src='http://latex.codecogs.com/gif.latex?S=C\cdot e^{K\cdot t}-\frac{a\cdot K\cdot (K\cdot sin(\omega\cdot t+p)+\omega\cdot...
  21. Wedge of Cheese

    Oh shit, I left out the S. That was supposed to say: <span rel='lightbox'><img...

    Oh shit, I left out the S. That was supposed to say: <span rel='lightbox'><img src='http://latex.codecogs.com/gif.latex?\frac{dS}{dt}=\frac{(a\cdot sin(\omega\cdot t+p)+S)\cdot k}{dt}' alt='Posted Image' class='bbc_img' /></span>
  22. Wedge of Cheese

    Oops, I probably shouldn't have put that S inside that mathrm, in fact I could have just omitted...

    Oops, I probably shouldn't have put that S inside that mathrm, in fact I could have just omitted the mathrm entirely, but whatevs. Anyway, we solve the diffEQ by separating the variables and integrating, but first, recall when I said:<p class='citation'>Quote</p><div class="blockquote"><div...
  23. Wedge of Cheese

    Yay, the LaTeX worked! <img...

    Yay, the LaTeX worked! <img src='http://www.cavestory.org/forums/public/style_emoticons/<#EMO_DIR#>/grin2.gif' class='bbc_emoticon' alt=':D' /> Anyways, we can now inductively prove that S is distributive over addition. Suppose f, g, and h are functions over the real numbers where...
  24. Wedge of Cheese

    Unless there's some really obvious slick mathematical trick I'm missing, it turns out to be...

    Unless there's some really obvious slick mathematical trick I'm missing, it turns out to be easier to prove that S is distributive over addition using the discrete representation rather than the continuous one. For our purposes, we'll consider the two interchangeable, since the only real...
  25. Wedge of Cheese

    A 6 chord is just a major chord with an extra note added a major 6th above the root. So G6...

    A 6 chord is just a major chord with an extra note added a major 6th above the root. So G6 would be G-B-D-E. And nao for sum postathon.
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